CHEM 1406 Measurement
Laboratory
(revised
Blood Glucose Measurement:
(BE SURE TO DISPOSE OF THE
USED TEST STRIP IN THE APPROPRIATE
MANNER
FOR A BILOGICAL HAZZARD!)
Meter
reading = ____________________
Time of
reading, ____________________
Circle
one:
Fasting or
Non-fasting
Data Analysis, Blood
Glucose Monitor
Define
- accuracy __________________________________________
_________________________________________________________
_________________________________________________________
Define
- precision __________________________________________
_________________________________________________________
_________________________________________________________
CHEM 1406
Blood Glucose
Measurements page 2
Data: Using the "glucose standard
solution" provided, take five separate glucose
readings. Record the five readings in the table
below. (These used test strips pose
no biological
hazard.)
Table 1: Observations
|
Sample # |
Observed reading |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Calculate
the mean (average) = _____________
Show work:
Complete
the following table:
Table
2, Calculations
|
Sample # |
Deviation from the mean [(mean value) - (sample value)] value D |
Square of deviation from the mean D2 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
CHEM 1406 Blood
Glucose Measurements page 3
from: http://www.chem.vt.edu/chem-ed/data/precision.html
Calculate the standard deviation
for the observed readings using the
"glucose
standard."
Standard deviation =
__________________
Calculation of the Standard Deviation:
(for ungrouped data)
The "Standard Deviation" for ungrouped data can be calculated in the
following steps:
1. all the deviations (differences) from the arithmetic mean of the set of numbers are squared;
2. the arithmetic mean of these squares is then calculated;
3. the square root of the mean is the standard deviation
Non-mathematical people always find this a bit complicated at first, but don't despair, there is an example to follow that should take the sting out of it.
Example:
Given the set of numbers {20, 23, 25, 26}, the "Standard Deviation"
can be calculated as follows:
Step 1:
The arithmetic mean of these numbers is found to be equal to 23.5
[eg. arithmetic mean = (20+23+25+26)/4 = 23.5]. The deviations from the mean
are respectively:
1. 23.5 - 20 = 3.5
2. 23.5 - 23 = 0.5
3. 25 - 23.5 = 1.5
4. 26 - 23.5 = 2.5
The squares of these deviations are:
1. 3.5^2 = 12.25
2. 0.5^2 = 0.25
3. 1.5^2 = 2.25
4. 2.5^2 = 6.25
Step 2: The sum of these
squares is 12.25 + 0.25 + 2.25 + 6.25 = 21. This is now divided by (n-1), which
is 3, to get 7.
NOTE: Some books show division by "n". However, when calculating the
Standard Deviation of small sample, a better estimate of the parent group is
obtained by dividing by (n-1) instead of dividing by "n". For large
"n", the difference between using "n" or "n-1" is
small.
Step 3:
Finally, the square root of 7 is approximately 2.6457513
Answer:
In summary, the Standard Deviation of the set of numbers {20, 23, 25, 26} is
2.6457513
From, http://www.bjmath.com/bjmath/Stats/sd.htm